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n^2+26n+144=0
a = 1; b = 26; c = +144;
Δ = b2-4ac
Δ = 262-4·1·144
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-10}{2*1}=\frac{-36}{2} =-18 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+10}{2*1}=\frac{-16}{2} =-8 $
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